-3d^2+6d-3=0

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Solution for -3d^2+6d-3=0 equation: 



-3d^2+6d-3=0

a = -3; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-3)·(-3)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{-6}{-6}=1$

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